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【Algorithm】 05050822222628 DL : 0: !逐步回归分析程序： ! M：输入变量，M=N+1，其中N为自变量的个数；M包括的因变量个数 ! K：输入变量，观测点数； ! F1：引入因子时显著性的F-分布值； ! F2：剔除因子时显著性的F-分布值； ! XX：存放自变量和因变量的平均值； ! B：存放回归系数； ! V：存放偏回归平方和和残差平方和Q； ! S：存放回归系数的标准偏差和估计的标准偏差； ! C：存放复相关系数； ! F：存放F-检验值；-! Stepwise regression analysis procedure:! M: input variables, M = N+ 1, in which N is the number of independent variables M, including the number of the dependent variable! K: input variables, observation points ! F1: when to introduce a significant factor of the F-distribution value ! F2: remove significant factor when the F-distribution value ! XX: storage self-variables and the dependent variable on average ! B: regression coefficient storage ! V: store partial regression sum of squares and residual sum of squares Q ! S: storage of the standard deviation of regression coefficients and the estimated standard deviation ! C: storage of multiple correlation coefficient ! F: storing F-test value
Update : 2024-05-20 Size : 2048 Publisher : wang hanting
【Special Effects】 sambhare DL : 0: matlab编写的纹理图像分割 gussian滤波后k-means聚类并将不同区域用线条表示出来除m程序还包括测试图片、pdf文件、ppt文件、doc文档-matlab prepared texture image segmentation gussian filtered k-means clustering in different regions and lines that come out with the exception of m program also includes test pictures, pdf file, ppt file, doc file
Update : 2024-05-20 Size : 2051072 Publisher : 程雪娇
【Other Games】 MIGONG DL : 0: 由0和1构成的n维方阵M表示一个迷宫，其中0表示通路，1表示墙壁。迷宫入口为(1,1),出口为(n,n)。迷宫随机产生。试编一算法求出从入口点到出口点可沿八个方向前进的一条通路。 -From 0 and 1 consisting of n-dimensional matrix M express a maze, where 0 indicated that access, said one wall. Maze entrance (1,1), export (n, n). Randomly generated maze. Test series 1 algorithm derived from the entrance point to the export of eight points along the direction of a path.
Update : 2024-05-20 Size : 6144 Publisher : 兜兜
【Mathimatics-Numerical algorithms】 Kmeans_EM_Delphi DL : 0: 这是一个关于k-means和E-M的比较文件,里面包括源代码和详细的试验报告-This is a study on k-means and EM comparison of documents, which include the source code and detailed test report
Update : 2024-05-20 Size : 1881088 Publisher : 李爱纳
【matlab】 Normalwhitenoise DL : 0: 产生正态白噪声序列 (1) 打印出前50个数 (2) 分布检验 (3) 均值检验 (4) 方差检验 (5) 计算相关函数 Bx(i),i=0,±1,±2,…, ±10。 B(m)=1/1000 -Have a normal white noise sequence (1) print out the top 50 the number of (2) the distribution of test (3) the mean test (4) of variance test (5) calculating the correlation function Bx (i), i = 0, ± 1, ± 2 , ..., ± 10. B (m) = 1/1000
Update : 2024-05-20 Size : 1024 Publisher : yanxiaoying
【CSharp】 8huanghou DL : 0: 算法流程：１、数据初始化。２、从n列开始摆放第n个皇后（因为这样便可以符合每一竖列一个皇后的要求），先测试当前位置(n,m)是否等于０（未被占领）：如果是，摆放第n个皇后，并宣布占领(记得要横列竖列斜列一起来哦)，接着进行递归；如果不是，测试下一个位置(n,m+1)，但是如果当n<=8,m=8时，却发现此时已经无法摆放时，便要进行回溯。３、当n>8时，便一一打印出结果。优点：逐一测试标准答案，不会有漏网之鱼。 -Algorithm processes: 1, data initialization. 2, from n to start out the first n-place Queen s (because it would be able to meet each vertical column of a Queen s request), first test the current position (n, m) is equal to 0 (not occupied): If yes, before let the first n of Queen s, and announced that the occupation (remember to put out oblique row out together Oh), followed by recursive If not, test the next location (n, m+ 1), but if n <= 8, m = 8, they found that at this time have been unable to display, it should be retroactive. 3, when n> 8, they all print out the results. Advantages: one by one testing standard answer, there will not be falling through the openings.
Update : 2024-05-20 Size : 1024 Publisher : 高慧
【CSharp】 nquene DL : 0: 算法流程：１、数据初始化。２、从n列开始摆放第n个皇后（因为这样便可以符合每一竖列一个皇后的要求），先测试当前位置(n,m)是否等于０（未被占领）：如果是，摆放第n个皇后，并宣布占领(记得要横列竖列斜列一起来哦)，接着进行递归；如果不是，测试下一个位置(n,m+1)，但是如果当n<=8,m=8时，却发现此时已经无法摆放时，便要进行回溯。３、当n>8时，便一一打印出结果。优点：逐一测试标准答案，不会有漏网之鱼。 -Algorithm processes: 1, data initialization. 2, from n to start out the first n-place Queen s (because it would be able to meet each vertical column of a Queen s request), first test the current position (n, m) is equal to 0 (not occupied): If yes, before let the first n of Queen s, and announced that the occupation (remember to put out oblique row out together Oh), followed by recursive If not, test the next location (n, m+ 1), but if n <= 8, m = 8, they found that at this time have been unable to display, it should be retroactive. 3, when n> 8, they all print out the results. Advantages: one by one testing standard answer, there will not be falling through the openings.
Update : 2024-05-20 Size : 1024 Publisher : 高慧
【matlab】 cycle_spinning DL : 0: 内含两个程序：1.平移变换平移法(cycle_spinning)消除gibbs(吉布斯)效应 2.MATLAB中测试程序运行时间的函数.m-Includes two procedures: 1. Translational transform translation (cycle_spinning) Elimination gibbs (Gibbs) 2.MATLAB effect of test procedures to run a function of time. M
Update : 2024-05-20 Size : 1024 Publisher :
【Other】 joseph DL : 0: 题目：约瑟夫环问题一．问题描述设有n个人围做一圈，现从某个人开始报数，数到m的人出列，接着从出列的下一个人开始重新报数，数到m的人又出列，如此下去，直到所有人都出列为止。试设计确定他们的出列次序序列的程序。 -Title: Joseph Central issues 1. Description of the problem has to do lap Wai n individuals, are reported from a few individuals to start, a few people out of the m out, and then a column from the next re-reported the number of individuals, several of the m out of people, so until all that far out. Test designed to determine whether they should set out the order of a sequence of procedures.
Update : 2024-05-20 Size : 1024 Publisher : wangshujing
【Special Effects】 wave_and_contourlet_denoise DL : 1: 运用contourlet变换和小波变换对图像进行去噪处理,并将二者的去噪效果通过PSNR进行对比.文中包含去噪.m文件和求PSNR的.m文件.程序中注释详细,值得参考.通过测试的代码.-Use Contourlet transform and wavelet transform for image denoising treatment, and the denoising effect of the adoption of both PSNR comparison. Paper contains denoising. M documents and PSNR for the. M file. Program notes in detail, it is also useful. Through test code.
Update : 2024-05-20 Size : 171008 Publisher : chy
【Other】 IEEE1394_testing_procedure DL : 0: IEEE 1394 hk4 TEST Progea,m and test fold
Update : 2024-05-20 Size : 604160 Publisher : VictorChang
【matlab】 sudo7matlab DL : 0: 這是一個求數獨遊戲的m-file 在matlab的命令窗口鍵入>> sudo7 或者run sudo7 的m-file 之後在 9x9 的方格內填入數獨的問題按下 "計算是否有解" 的功能鍵若不是存在多組的解，則可以按下 "顯示結果" 的功能鍵，也可以載入作者測試的"date1"或"date2" 但不可載入及修改"condition"-This is a Sudoku game for the m-file in matlab command window type>> sudo7 or run sudo7 the m-file after the box in the 9x9 Sudoku Fill in the question of pressing the calculate whether the solvability feature key if it were not for the existence of multiple solutions, you can press the show results of the function keys can also be included in the authors test date1 or date2 but not loading and modification of condition
Update : 2024-05-20 Size : 19456 Publisher : ho io tong
【Other】 cmbn DL : 0: A RUBY class for generating n-element combinatatorials of any m elements (indexed by [0,1,...m-1]): C(m, n) To test, first uncomment the test block. Then run: >ruby cmbn.rb 7 4 ==> C(7, 4) or >ruby cmbn.rb 7 ==> {C(7,0), C(7,1), ..., C(7,7)}
Update : 2024-05-20 Size : 1024 Publisher : wj chen
【matlab】 mktest DL : 0: m-k检验，用于进行m-k检验突变所发生的时间-mk test, used for testing mk mutation occurred at a time
Update : 2024-05-20 Size : 1024 Publisher : 孙敏
【Data structs】 Apple_Set DL : 0: Problem A:放苹果 Time Limit:1000MS Memory Limit:65536K Total Submit:1094 Accepted:441 Language: not limited Description 把M个同样的苹果放在N个同样的盘子里，允许有的盘子空着不放，问共有多少种不同的分法？（用K表示）5，1，1和1，5，1 是同一种分法。 Input 第一行是测试数据的数目t（0 <= t <= 20）。以下每行均包含二个整数M和N，以空格分开。1<=M，N<=10。 Output 对输入的每组数据M和N，用一行输出相应的K。 Sample Input 1 7 3 Sample Output 8-Problem A: Apple released Time Limit: 1000MS Memory Limit: 65536KTotal Submit: 1094 Accepted: 441 Language: not limitedDescription to M of the same apple on the N plate of the same, allowing some empty onto a plate and asked the total number of different types of sub-law? (Indicated by K) 5,1,1 and 1,5,1 is the same method. Input the first line is the number of test data t (0
Update : 2024-05-20 Size : 157696 Publisher : 杨扬
【ARM-PowerPC-ColdFire-MIPS】 UART0_int DL : 0: ARM UART中断处理啊试验AR M UART中断处理啊试验-ARM UART interrupt handling test ah AR M UART interrupt handling test ah
Update : 2024-05-20 Size : 106496 Publisher : 黎明
【matlab】 MPSKMQAMmudulation DL : 0: 本程序用于完成BPSK、QPSK、pi/4QPSK、OQPSK、8PSK、16QAM、32QAM、64QAM和128QAM的调制仿真。并可任意扩展到MPSK和MQAM。程序分成四个部分，fir.m对基带码元序列进行脉冲成型，可选矩形脉冲，升余弦脉冲和平方根升余弦脉冲； modal.m 为主程序，完成岁各种信号的基带星座图映射、脉冲成型和调制；pi4QPSK.m 为pi/4QPSK信号的星座图映射程序；test1.m给出一个简单的频谱显示测试。-This procedure for the completion of BPSK, QPSK, pi/4QPSK, OQPSK, 8PSK, 16QAM, 32QAM, 64QAM and the modulation 128QAM simulation. Arbitrary and may be extended to MPSK and MQAM. Procedures are divided into four parts, fir.m of baseband symbol pulse sequences forming, optional rectangular pulse, raised cosine square root raised cosine pulse and pulse modal.m-based procedures, the completion of the age range of the base-band signal constellation diagram mapping, pulse shaping and modulation pi4QPSK.m for pi/4QPSK signal constellation diagram mapping procedures test1.m given spectrum shows a simple test.
Update : 2024-05-20 Size : 4096 Publisher : 徐哲
【Speech/Voice recognition/combine】 VQ DL : 0: 在MATLAB环境下实现基于矢量量化的说话人识别系统。在实时录音的情况下，利用该说话人识别系统，对不同的人的1s～7s的语音进行辨识。实现与文本无关的自动说话人确认的实时识别。使用说明： 1 训练打开Matlab 使Current Directory为VQ所在的文件夹(比如：E:\vq) 在Command windows中输入 train( 1s\ ,7) 这是将1s中的wav文件进行特征提取并产生VQ码本，在workspace中有个ans的文件保存为.m文件，比如7.m，保存在1s文件夹下。（1s表示语音长1秒） 2 识别在Command windows中输入 test( 4s/ ,7,ans) 其中的ans 就是步骤1产生的码本。（必须保证7.m在workspace中打开）此时就会显示结果。 Speaker 1 matches with speaker 2 Speaker 2 matches with speaker 3 Speaker 3 matches with speaker 4 Speaker 4 matches with speaker 6 Speaker 5 matches with speaker 2 Speaker 6 matches with speaker 7 Speaker 7 matches with speaker 7 1s、4s分别是7个不同的人说话的录音，只是打乱了次序。-err
Update : 2024-05-20 Size : 466944 Publisher : 晶晶
【Com Port】 uart DL : 0: UATR0 试验,从串口以9600,N,1的模式循环输出16进制的-UATR0 test, from the serial port to 9600, N, 1 cycle of the output of the model of 16 M
Update : 2024-05-20 Size : 7168 Publisher : 宛玉
【Embeded-SCM Develop】 uart DL : 0: UATR0 试验,从串口以9600,N,1的模式循环输出16进制的-UATR0 test, from the serial port to 9600, N, 1 cycle of the output of the model of 16 M
Update : 2024-05-20 Size : 11264 Publisher : 宛玉

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