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Category : Communication
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- Update : 2012-11-26
- Size : 1kb
- Downloaded ：0次
- Author ：张于
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DW 256 DUP (?) STACK1 ENDSDDATA SEGMENTMES1 DB The least number is: $ MES2 DB 0AH, 0DH, The largest number is: $ NUMB DB 0D9H, 07H, 8BH, 0C5H, 0EBH, 04H, 9DH, 0F9HDDATA ENDSCODE SEGMENT ASSUME CS: CODE, DS: DDATASTART: MOV AX, DDATA MOV DS, AX MOV SI, OFFSET NUMB MOV CX, 0008H JCXZ A4 MOV BH, [SI] MOV BL, BHA1: LODSB AL = DS: [SI], SI = SI+ 1 CMP AL, BH JBE A2 MOV BH, AL JMP A3A2: CMP AL, BL JAE A3 MOV BL, ALA3: LOOP A1A4: MOV DX, OFFSET MES1 show mes1 MOV AH, 09H INT 21H MOV AL, BL show the least number AND AL , 0F0H get the highest 4 bits SHR AL, 4 CMP AL, 0AH JB C2 ADD AL, 07H C2: ADD AL, 30H MOV DL, AL show character MOV AH, 02H INT 21H MOV AL, BL AND AL, 0FH get the lowest 4 bits CMP AL, 0AH JB C3 ADD AL, 07HC3: ADD AL, 30H MOV DL, AL show character MOV AH, 02H INT 21H MOV DX, OFFSET MES2 show mes2 MOV AH, 09H INT 21H
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