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【matlab】 s_stcOCML2GNS DL : 0: Matlab里计算高维时空混沌OCML的源程序-Matlab to calculate high-dimensional space-time source of chaos OCML
Update : 2024-05-18 Size : 1024 Publisher : 冯云帆
【Other】 GPAjisuan DL : 0: 是老师布置下来的,总算完成了,是用来计算GPA的,希望对其他朋友有帮助-teachers from the layout, and finally completed, it is used to calculate the GPA, and I hope to help other friends
Update : 2024-05-18 Size : 31744 Publisher : yaobo
【transportation applications】 packing2006code DL : 0: 此程序目的用来计算集装箱装量，可以计算出达到最大装量的放置方法，功能已经基本实现，实际可以用于任何方形空间存放方形物体的计算问题，目前只有文字输出结果。程序利用回溯探索法，算法一般，有水平者可以改进算法。-purpose of the procedure used to calculate container load can be calculated maximum load placed methods, functions have basically achieved, the actual square can be used for any storage space of a square object computing problems, but currently only the text output. Back to explore the use of procedures, the general algorithm, a standard algorithm can be improved.
Update : 2024-05-18 Size : 3683328 Publisher : 李永兴
【JSP/Java】 BigIntMultiplication DL : 0: 大整数乘法例子代码 /* 递归边界，如果是1位二进制数与1位二进制数相乘，则可以直接计算 */ /*累计做1位二进制乘法运算的次数*/ /* return (X*Y) */ /* 计算n的值 */ /* 把X和Y拆分开来，令X=A*2^(n/2)+B, 左移位运算，mod = 1<<(n/2) */ /* 计算XY=AC*2^n+(AD+CB)*2^(n/2)+BD */ /* 计算A*C，再向左移n位 */ /* 递归计算A*D */ /* 递归计算C*B */ /* 计算a21+a22,再向左移n/2位 */ /* 递归计算B*D */ /* XY=a1+a2+a3 */ -large integer multiplication example code/* Recursive border, if it is a binary number with a binary number multiplication, can be directly calculated*//* the beginning of a binary multiplication of the number*//* return (X* Y)*//* calculate the value of n*//* X and Y to split it so that X = A* 2 ^ (n/2) B, the left shift operator, mod = 1LT; lt; (n/2)*//* calculate XY = AC* 2 ^ n (AD CB)* 2 ^ (n/2) BD*//* A* C calculation, further n-bits*//* recursive computation A* D*//* recursive calculation of C* B*//* Calculation A21 A22 and then bits n/2*//* recursive calculation B* D*//* XY = a1 a2 a3* /
Update : 2024-05-18 Size : 1024 Publisher : 小城
【Other】 24fan DL : 0: 利用后缀表达式来计算，穷举四个数的所有后缀表达式，然后计算它，能算出24的就是答案了-expression to use the suffix, several exhaustive of all four suffixes expression, then calculate it can calculate 24 is the answer
Update : 2024-05-18 Size : 2048 Publisher : 潘洪峰
【Graph Recognize】 wenlifenxi DL : 0: 图像的纹理分析方法,计算图像的纹理参数等-image texture analysis methods to calculate the texture parameters
Update : 2024-05-18 Size : 440320 Publisher : wade
【AI-NN-PR】 haplotyper.1.0.LINUX.tar DL : 0: 利用Partition-Ligation algorithm计算生物SNP的单倍型频率-use Partition- Ligation algorithm to calculate the SNP haplotype frequencies
Update : 2024-05-18 Size : 53248 Publisher : 孙学科
【CSharp】 repeat DL : 0: 最长重复子串问题 .问题描述：在一个特定字符串str 中，多次出现的子串称为重复子串。如果字符串str 中有多个重复子串，则其中长度最长的子串称为最长重复子串。例如，str=’abcdacdac’ ，则子串’cdac’ 是str 的最长重复子串。 .编程任务：给定一个字符串str ，编程计算str 的最长重复子串。-longest repeated substrings problems. Problem description : In a specific string str, repeated substrings called repeated substrings. If the string str There were several repeat substrings, which the length of the longest substrings called the longest repeat substrings. For instance, str = 'abcdacdac', substrings' cdac 'is the longest repeat str substrings. . Programming tasks : to set a string str, programmed to calculate the longest str repeat substrings.
Update : 2024-05-18 Size : 46080 Publisher : 无翼
【Other systems】 prob DL : 0: 用于计算贝叶斯频谱概率，可用于实际工程！！!-used to calculate the Bayesian probability spectrum can be used for actual works! ! !
Update : 2024-05-18 Size : 1024 Publisher : chen
【Other】 jisuanriqishidijitian DL : 0: 计算是这年的的第几天（判断闰年）能判断月份是否输入错误,如果是闰年还能计算2月份的日期输入是否过界!算法还算不错!-calculation is that the days of (determining a leap year) in the ability to determine whether an input error, If it is a leap year in February can calculate the date and whether community input! Algorithm quite well!
Update : 2024-05-18 Size : 8192 Publisher : 宇宙的弦
【Mathimatics-Numerical algorithms】 xianxinghuigui DL : 0: 一个简单的线性回归程序。可以用来计算线性回归。-a simple linear regression procedure. Used to calculate linear regression.
Update : 2024-05-18 Size : 1024 Publisher : hou
【Mathimatics-Numerical algorithms】 FDTD_TM_PC DL : 0: 这个程序是用来计算二维光子晶体光波导（仅限于TM模）的传输特性的-This procedure is used to calculate two-dimensional photonic crystal waveguide (TM mode is limited to) the transmission characteristics of
Update : 2024-05-18 Size : 4096 Publisher : 冯金顺
【Mathimatics-Numerical algorithms】 one-dimension DL : 0: 这几个程序是用于计算一维光子晶体反射系数和透射系数的-these procedures are used to calculate the one-dimensional photonic crystal reflection and transmission coefficients of
Update : 2024-05-18 Size : 3072 Publisher : 冯金顺
【TreeView】 zstree DL : 0: 这是一个计算油田注水系统效率的例子,通过操作tree表达的油田注水系统网络结构,可很容易地计算出油田注水系统效率-This is a calculated oilfield injection system efficiency example, tree expression through the operation of the oil field water injection system network architecture, can easily calculate the oilfield water injection system efficiency
Update : 2024-05-18 Size : 7168 Publisher :
【DNA】 chromosome DL : 0: 文件中有程序源代码，计算软色体的交叉概率和变异概率-document is the source code to calculate the soft-color cross- mutation probability and the probability
Update : 2024-05-18 Size : 2048 Publisher : 王沪龙
【GUI Develop】 DBGrid-mutiple-head DL : 0: 轻松实现DBGrid多表头加强版网上流传的TADBgrid控件可以轻松实现DBGrid多表头，不过它的设计较简单，相邻字段，层数必须相同才可以合并，这样效果就大打折扣了，我本来给他 90分的，就这一点就扣了89分。我下功夫改了一下，即使层数也可以合并，还做到最底层的高度尽量小，效果与DBGridEh几乎一样，因为比较简单，没有解决折行，这需要在内存做一棵树来计算高度，复杂些，可参考DBGridEH, 下面就是实现的代码，如果发现有错，请指出改正。-easily DBGrid strengthen multi-table first version TADBgrid spread of the Internet can easily control it now DBGrid multi-table heads, but its design is relatively simple, adjacent fields, the same rise can be merged, this effect will be greatly reduced, I would have to give him 90 points, on this point deduction of 89 points. I make efforts to reform it, and even floors also can be combined, but also achieve a high degree of the bottom as possible, effects DBGridEh almost the same as it is more simple, no address lines, This needs to do in memory to calculate a tree height, more complex, reference DBGridEH. Below is the realization of the code, if found to be wrong, please correct that.
Update : 2024-05-18 Size : 3072 Publisher : cy
【Other】 mypro3final DL : 0: 用java写的可以计算一张图中的关键路径的程序速度还可以-written with java can calculate a map of the critical path of procedures can also speed
Update : 2024-05-18 Size : 10194944 Publisher : 陈减肥
【Education soft system】 25175xscjcx224 DL : 0: 能自动计算总分、平均分及格率等各种统计数据。在统计时你还可以选择统计全部学科或部分学科；在使用中可自由增删成绩、人员，学科，及学科改名功能；自由设置卷面总分、及格线、分数段间隔、综合分，学校名，用户名，背景等.-can automatically calculate scores, average passing rates and other statistics. In statistics, you can also choose the part of all disciplines or subjects; The use of free additions accomplishments, staff, disciplines, renamed and functional disciplines; the freedom accessories scores, the line to pass, scores of layout, integrated, schools, user name, background.
Update : 2024-05-18 Size : 115712 Publisher : lyj
【Windows Develop】 reply_1_855734 DL : 0: // Canny算子 void Canny(LPBYTE pGray, SIZE sz, double sigma, double dRatLow, double dRatHigh, LPBYTE pResult) { //经过高斯滤波后的图像 LPBYTE pGaussSmooth pGaussSmooth = new unsigned char[sz.cx*sz.cy] //x方向导数的指针 int *pGradX pGradX = new int[sz.cx*sz.cy] //y方向 int *pGradY pGradY = new int[sz.cx*sz.cy] //梯度的幅度 int *pGradMag pGradMag = new int[sz.cx*sz.cy] //对原图高斯滤波 GaussianSmooth(sz,pGray,pGaussSmooth,sigma) //计算方向导数和梯度的幅度 Grad(sz,pGaussSmooth,pGradX,pGradY,pGradMag) //应用非最大抑制 NonmaxSuppress(pGradMag,pGradX,pGradY,sz,pResult) //应用Hysteresis，找到所有边界 Hysteresis(pGradMag,sz,dRatLow,dRatHigh,pResult) delete[] pGradX pGradX = NULL delete[] pGradY pGradY = NULL -//Canny operator void Canny (LPBYTE pGray. SIZE sz, double sigma, double dRatLow. double dRatHigh. LPBYTE pResult) (//after Gaussian filtering of images LPBYTE pGaussS mooth unsigned pGaussSmooth = new char [sz.cx* sz.cy]// x direction derivative indicators pGradX pGradX int* = new int [ sz.cx* sz.cy]// int* y direction pGradY pGradY = new int [sz.cx* sz.cy]// gradient magnitude int* pGradMag pGradMag = new int [sz.cx* sz.cy]// maximum Gaussian filter to GaussianSmo oth (sz, pGray, pGaussSmooth. sigma)// calculate derivative and the gradient range Grad (sz. pGaussSmooth, pGradX, pGradY. pGradMag)// non-application of the biggest inhibition NonmaxSuppress (pGradMa g, pGradX, pGradY, sz, pResult)// Application Hysteresis, find all border Hysteresis (pGradMag, sz, dRa
Update : 2024-05-18 Size : 54272 Publisher : 王学金
【CSharp】 BookSales DL : 0: 目前公司有一笔很大的买卖，对所有图书提供15％的折扣，这个项目中，会计算一定数量的图书的应付金额、确定15％的折扣，扣除折扣并得到新的应付金额-打折后的金额-So far the company has a lot of the sale of all books offers a 15% discount, the project, calculate the number of books to cope with the amount of the 15% discount, After discounting the effect of discounts and to a new deal with the amount-after rebate amount
Update : 2024-05-18 Size : 31744 Publisher : 甘露

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