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【SourceCode】 calculate.rar DL : 0: 一个复数计算的程序
Update : 2024-05-18 Size : 1072 Publisher :
【Mathimatics-Numerical algorithms】 Caculator DL : 0: 有二叉树计算表达式的值-a binary tree calculate the value of the expression
Update : 2008-10-13 Size : 35468 Publisher : 李艾
【Mathimatics-Numerical algorithms】 calc_3 DL : 0: 数学表达式计算器，VC 平台操作。能够计算数学公式和表达式，功能比较强大。-mathematical expression calculator, VC platform operators. To calculate mathematical formula and expression, function more powerful.
Update : 2008-10-13 Size : 80210 Publisher : 余卫军
【Windows Develop】 expr DL : 0: 可以计算各种函数，还可以使用变量，如A，B，C，D。可以计算各种数学函数sin cos tg ctg,处理括号，四则运算，是VC中一款不可多得的表达式计算类和计算工具。例如：cos(0) 1-can calculate various functions, variables can also be used, such as A, B, C, D. Can calculate mathematical functions sin cos tg rays, handling brackets, four operators, one VC is a rare expression of calculating and computing tools. For example : cos (0) 1
Update : 2008-10-13 Size : 45263 Publisher : 何福保
【Other】求24点，学递归 DL : 0: 求算24点是一个极为有趣的大众智力游戏,深得许多人的喜欢。但你有没有遇到过求不出解的情况呢?是自己没有想出来还是确实无解?很难判断吧!有没有想过用电脑来求解呢。如果你有一点点VB的基础,那就让我们一起来看看该怎样用VB来求算24点吧。-calculating 24 is a very interesting public intellectual games, won many people like it. But you have never met before seeking solutions not happen is they did not come up with no solution or indeed is very difficult to judge! Have you ever thought of using computers to solve it. If you have a little bit of VB foundation, then let us look at how to use VB to calculate 24 spot.
Update : 2008-10-13 Size : 2783 Publisher : 佳闲
【ADO-ODBC】 expresstest DL : 0: 求算术表达式的结果，先输入一个四则运算规则（包括乘方）的表达式，然后计算其结果-arithmetic expression for the results to input a four Operational rules (including involution) of the expression, and then calculate the results
Update : 2008-10-13 Size : 12015 Publisher : 周国材
【Windows Develop】 FiveSource DL : 0: 本代码是一个完整的小游戏,界面美观,其中的人工智能算法也很值得参考学习.-This code is artificial intelligence calculate way that a complete get-away drama, the interface is beautiful, among them too worthwhile consult study
Update : 2008-10-13 Size : 134323 Publisher : 杨杰
【Windows Develop】 AESDemo DL : 0: AESDemo应用例程 AES（The Advanced Encryption Standard）是美国国家标准与技术研究所用于加密电子数据的规范。它被预期能成为人们公认的加密包括金融、电信和政府数字信息的方法。本文展示了AES的概貌并解析了它使用的算法。包括一个完整的C#实现和加密.NET数据的举例。在读完本文后你将能用AES加密、测试基于AES的软件并能在你的系统中使用AES加密。-The AESDemo application a distance AES( The Advanced Encryption Standard) is a norm that ASCII used for with technique graduate school to encrypt the electronics data.It were expected and can become people encrypt to include the finance, telecommunication generally acceptedly with the method of the government arithmetic figure information.This text displayed the AES all the combines resolution the calculate way that it use.Include a complete C# realizes with encrypt.The data of NET for instance.Use in a reading book over text empress you will can with the AES encrypt, test base on AES software combine can in your system the AES encrypt
Update : 2008-10-13 Size : 34252 Publisher : 杨康
【Other】 fft DL : 0: This is a package to calculate Discrete Fourier/Cosine/Sine Transforms of 1-dimensional sequences of length 2^N. This package contains C and Fortran FFT codes.
Update : 2008-10-13 Size : 72183 Publisher : 陈西
【Other resource】 MonteCarloEuro DL : 0: 蒙特卡洛模拟来计算欧式期权的定价，更忌精确但是耗时很大。-Monte Carlo simulation to calculate European option pricing, more accurate but time-consuming bogey great.
Update : 2008-10-13 Size : 1906 Publisher : 真实
【Other resource】最短距离问题 DL : 0: 求解网络中的最短路径。假设某个计算机网络有n个站点，依次编号为1,2,…,n；有的站点之间有直接的线路连接（即这两个站点之间没有其它站点），有的站点之间没有直接的线路连接。如果用三元组（i,j,f）来表示该网络中的站点I和站点j之间有直接的线路连接且它们之间的距离为f 当已知该网络各站点之间的直接连接情况由m个三元组（i1,j1,f1）,(i2,j2,f2),…,(im,jm,fm)确定时，要求计算出对于网络中任意一个站点g(1≤g≤n)到其余各站点的最短距离。-the shortest path. Assuming a computer network n site, followed by No. 1, 2, ..., n; Some sites have direct connections (that is, between two sites are no other site), and some sites have no direct connections. If three yuan (i, j, f) to the network said the site j site and I have direct connections between them but the distance of f the network known as the site of the direct link between the situation by 3 m (i1, j1, f1), ( i2, j2, f2), ..., (im, jm, fm) to determine, calculate requirements for a network site arbitrary g (1 g n) of the rest of the site is the shortest distance.
Update : 2008-10-13 Size : 10120 Publisher : 葛林
【Other resource】 MD5加密的C++类 DL : 1: 这是一个好用的MD5的C++类；这个类可以加在控制台程序中也可用在MFC中，并且提供了详细的错误处理函数，是一个安全的类。例程是一个MD5的MFC程序，支持字符串和文件两种输入。 LPCSTR TargetFile(char *filename=NULL) //计算文件的MD5值 void TargetStr(LPCSTR str) //计算字符串的MD5值 LPCSTR GetDigestKey() //取MD5运算后的结果 LPCSTR GetErr() //如果有错误，取错误字串-This a user-friendly MD5 C; This category can be added to the Console program is available in MFC, and provided a detailed error handling function, is a safety class. MD5 is a routine MFC procedures, and documentation to support a string of two input. LPCSTR TargetFile (char * filename = NULL) / / calculate MD5 value of the document void TargetStr (LPCSTR str) / / calculate MD5 string value LPCSTR GetDigestKey () / / Operational MD5 from the results LPCSTR GetErr () / / If there were mistakes from the wrong string
Update : 2008-10-13 Size : 4533 Publisher : 俞训峰
【assembly language】 DIV4P DL : 0: MCS51四字节除法运算程序，可计算出四字节的商和四字节的余数。-mcs51 division operation routine for tetra-byte ,may calculate both quotient of tetra-byte and remaining of tetra-byte
Update : 2008-10-13 Size : 1591 Publisher : 张希刚
【Dialog_Window】判断润年 DL : 0: 这是一个判断闰年的小程序，只要你随意输入一个年份，程序就会自动帮你算出是不是闰年，并显示结果给你看！-This is a small leap year judgment procedures, as long as you can input a year, procedures will automatically help you calculate it is not a leap year, and the result will be displayed for you!
Update : 2008-10-13 Size : 138346 Publisher : 戚
【Other】 wors_in_mind DL : 0: 一个很好的背诵单词的工具，可以自动计算时间，里面含有大量单词库。-a good tool to memorize words, it will automatically calculate time, it contains a large number of words for.
Update : 2008-10-13 Size : 3447458 Publisher : 陈
【Other resource】 mesch12b自己修正 DL : 0: C语言版本的矩阵库，目前世界上最流行的三大矩阵运算库之一，这是修正版本，我自己改了几个地方（按照官方要求）-C language edition matrix library , now in the world the most popular three greatest matrixeses carries to calculate the one of the library , this is to revises the edition, myself changed a few places( request according to the authorities)
Update : 2008-10-13 Size : 709099 Publisher : 赵辉
【Other resource】离散系统分析 DL : 0: 已知一个LTI系统的差分方程为： y[n]-1.143*y[n-1]+0.4128*y[n-2]=0.0675*x[n]+0.1349*x[n-1]+0.0675*x[n-2] 初始条件y(-1)=1,y(-2)=2，输入x(n)=u(n)，计算系统的零输入响应 -known LTI system of a differential equation : y [n] -1.143 * y [n-1] 0.4128 * y [n-2] x = 0.0675 * 0.1349 [n] * x [n -1] 0.0675 * x [n-2] initial conditions y (1) = 1, y (2) = 2, input x (n) = u (n), we calculate the zero input response
Update : 2008-10-13 Size : 50578 Publisher : 殷开
【Windows Develop】 eigcnvalue DL : 0: n维矩阵的特征值的一种新求法，可实现特征值特征向量的求值-a new algorithm to calculate the aigenvalue of N dimensions matrix, aigenvalue and aigenvector can be worked out.
Update : 2008-10-13 Size : 5543 Publisher : 冰城
【Windows Develop】 InterpolationHermiteIsometry DL : 0: 艾尔米特等距插值。给定n个不等距节点的函数值及一阶导数值，使用埃尔米特插值公式计算指定插值点t处的函数近似值-Hermite Isometry Interpolation: to calculate the approximation of the function at the specified interpolation point t by using Hermite Isometry Interpolation function, which is based on the function value and first derivative value of N trimetry nodes
Update : 2008-10-13 Size : 74199 Publisher : 球球
【matlab】 Leap year calculate DL : 0: Leap year calculate by matlab.
Update : 2021-03-28 Size : 481 Publisher : alsand

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